x^2+105x=195

Solution for x^2+105x=195 equation:

x^2+105x=195

We move all terms to the left:

x^2+105x-(195)=0

a = 1; b = 105; c = -195;
Δ = b2-4ac
Δ = 1052-4·1·(-195)
Δ = 11805
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{11805}}{2*1}=\frac{-105-\sqrt{11805}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{11805}}{2*1}=\frac{-105+\sqrt{11805}}{2}
$